Question 474231
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Find the length of a rectangular lot with a perimeter of P if the length is d units more than the width.


Let *[tex \Large l\ =\ w\ +\ d\ \ \Rightarrow\ w\ =\ l\ -\ d] represent the length.  Let *[tex \Large w] represent the width.


The Perimeter is given as P, but we know that *[tex \Large P\ =\ 2l\ +\ 2w]


Substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2l\ +\ 2(l -\ d)\ =\ P]


Solve for *[tex \Large w] in terms of *[tex \Large P] and *[tex \Large d]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\ =\ \frac{P\ +\ 2d}{4}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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