Question 49058
y=x^2+x-6 [Use the quadratic formuala to solve]
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} [Quadratic Formula]
.
{{{x = (-1 +- sqrt( 1^2-4*1*-6 ))/(2*1) }}}  [Plug-in the values]
a=1
b=1
c=-6
.
{{{x = (-1 +- sqrt( 25 ))/(2) }}} [Simplify]
.
{{{x = (-1 +- (5 ))/(2) }}} 
.
{{{x = (-1 + (5 ))/(2) }}} 

{{{x = ((4))/(2)) }}}
x = 2
.

{{{x = (-1 - (5 ))/(2) }}}

{{{x = ((-6 ))/(2)) }}}
x=-3
So, x = 2 or x = -3