<PRE><B>Question 474211</B>
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Let *[tex \Large x] represent the measure of *[tex \Large \angle{ABC}].  Then *[tex \Large 9x] must represent the measure of *[tex \Large \angle{PQR}].  The sum of the measures of supplementary angles is *[tex \Large 180^\circ].  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9x\ +\ x\ =\ 180]


Solve for *[tex \Large x], then calculate *[tex \Large 9x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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