Question 474176
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Hi,
finding the center of a circle with the equation
Note: Standard Form of an Equation of a Circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
where Pt(h,k) is the center and r is the radius

x^2 + y^2 + 2x + 4y – 9 = 0  |completing Squares
 (x+1)^2 -1 + (y + 2)^2 -4  -9 = 0
   (x+1)^2 + (y+2)^2 = 14
    C(-1,-2)