Question 473895
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Hi,
Note: the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x)= -(x+8)^2 -3

V(-8,-3), a = -1, -1<0, Parabola open downward.  Vertex is a max point
x = -8 is the line of symmetry. Maximimum value for the functions is -3
The vertex = (-8,-3)
The line of symmetry = x = -8
The minimum or maximum value= -3
Is this maximum or minimum  max value
{{{drawing(300,300,  -10,10,-10,10,  blue(line(-8,10,-8,-10))  , grid(1),
circle(-8, -3,0.4),
graph( 300, 300, -10,10,-10,10,0,-(x+8)^2 -3
 ))}}}