Question 474116
At 06:00 hours two joggers start from opposite ends of an 8- km course.
 One jogger is running at 4km/hour and the other is running as a rate of 6km/hour .
At what time will the joggers meet?
:
Let t = no. of hrs after 6:00 that they will meet
:
When they meet, the total dist of the two runners will be 8 km
:
Write a distance equation dist = speed * time
4t + 6t = 8
10t = 8
t = {{{8/10}}}
t = .8 hrs or .8(60) = 48 min
:
They will meet at 6:48