Question 473619
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi, 
Find the coordinates of the turning point of the curve 
{{{y = -x^2 +4x+6}}}  |Turning point is the Vertex of the Parabola
  y = -[x^2 - 4x] + 6
  y = -[(x-2)^2 - 4] + 6
  y = -(x-2)^2 + 10  V(2,10), the turning point
       a = -1 -1<0, Parabola opens downward, turning point is a maximum

{{{drawing(300,300, -15,15,-15,15,  blue(line(2,15,2,-15))  , grid(1),
circle(2, 10,0.3),
graph( 300, 300, -15,15,-15,15,0,-x^2 +4x+6))}}}