Question 474037
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
{{{(x+2)/5 = 4/(x+1)}}}  |Cross Multiplying to solve
    (x+2)(x+1) = 20
    x^2 + 3x + 2 = 20
    x^2 + 3x - 18 = 0
factoring
   (x+6)(x-3) = 0
   (x+6)=0   x= -6  Extraneous solution(CANNOT divide by zero)
   (x-3) = 0   x = {{{highlight(3)}}}  AND 5/5 = 4/4 = 1 (checking out answer)

the 2nd is completed in a similar manner