Question 474009
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
{{{((a^2-3a^2)/(b^2+2b))*((b^2-4)/(a^2b-3ab))/((ab-2a)/b^2))}}}
{{{(-2a^2/b(b+2))*((b-2)(b+2)/ab(a-3))/(a(b-2)/b^2))}}}
{{{ ((-2a^2)/ab^2(a-3))/(a/b^2) = (-2)/(a-3)}}}