Question 474007
{{{((x^2+2x-15)/(9-x^2))*((x^2-3x-18)/(x^2-7x+6))=((x-3)(x+5)/(3-x)(3+x))*((x-6)(x+3)/(x-1)(x-6))=(cross((x-3))(x+5)cross((x-6))cross((x+3)))/(-cross((x-3))cross((x+3))(x-1)cross((x-6)))=-(x+5)/(x-1)=(x+5)/(1-x)}}}