Question 473933
P(own a car)=P(C)=67/100=0.67
P(own a bicycle)=P(B)=22/100=0.22
P(own car & bicycle) = P(C∩B) = 11/100=0.11
P (own car or bicycle) P(CUB)=?
P(CUB)=P(C)+P(B)- P(C∩B)
	=(0.67+0.22)-0.11
	=0.89-0.11
	=0.78