Question 473954
the discriminant 
{{{D=b^2-4ac}}}
{{{x^2-2x+5=0}}}
{{{a=1}}}, {{{b=-2}}}, {{{c=5}}}
{{{D=(-2)^2-4*1*5=-16<0}}}
the discriminant <0, so the equation has two non-real numbers
Answer 	A. Two non-real numbers.