Question 473924
Train A has a head start of how many miles when
train B passes the station?
10:37 - 10:25 = 12 minutes
Train A's head start is:
{{{ d[1] = 100*(12/60) }}}
{{{ d[1] = 20 }}} mi
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Now start a stopwatch when B passes the station.
Both trains will travel for the same amount of time, {{{t}}}
until they meet.
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Let {{{ d }}} = the distance that B has to go until they meet
Then {{{ d - 20 }}} = the distance that A has to go until they meet
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For B:
(1) {{{ d = 125t }}}
For A:
(2) {{{ d - 20 = 100t }}}
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Substitute (1) into (2)
{{{ 125t - 20 = 100t }}}
{{{ 25t = 20 }}}
{{{ t = 20/25 }}}
{{{ t = 4/5 }}} hrs
They will meet in {{{ 4/5 }}} hrs or {{{ (4/5)*60 = 48 }}} minutes
after B leaves station 
10:37 AM + 48 min = 11:25 AM is the time
B passes A
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check answer:
A's distance from station is {{{d}}}
A's time from station is {{{ 12/60 + 4/5 = 1 }}} hr
{{{ d = 100*1 }}}
{{{ d = 100 }}} mi
B's distance from station is also {{{d}}}
{{{ d = 125*(4/5) }}}
{{{ d = 100 }}} mi
OK