Question 473872
{{{x = -sqrt(y)}}}
Substitute into the bottom equation:

{{{y^2 - 2y = 3}}}, or {{{y^2 - 2y - 3 = 0}}}

<==> (y - 3)(y + 1) = 0 ==> y = 3, -1

eliminate y = -1 (Why?)

==> {{{x = -sqrt(3)}}}

The solution point is thus ({{{-sqrt(3)}}}, 3)