Question 473783
solve for x
{{{1/x}}} + {{{1/(x+3)}}} = {{{1/2}}}
multiply by 2, results
{{{2/x}}} + {{{2/(x+3)}}} = 1
Multiply by x(x+3), results:
2(x+3) + 2x = x(x+3
2x + 6 + 2x = x^2 + 3x
4x + 6 = x^2 + 3x
0 = x^2 + 3x - 4x - 6
x^2 - x - 6 = 0