Question 473797

{{{2z/(z^2-16) + z/(z-4)}}}....


={{{2z/(z^2-4^2) + z/(z-4)}}}


={{{2z/((z-4)(z+4)) + z/(z-4)}}}


={{{2z/((z-4)(z+4)) + z(z+4)/((z-4)(z+4))}}}


={{{(2z + z(z+4))/((z-4)(z+4))}}}


={{{(2z +z^2+4z)/((z-4)(z+4))}}}


={{{(z^2+6z)/((z-4)(z+4))}}}


={{{z(z+6)/((z-4)(z+4))}}}