Question 49034
first integer = i
second integer = i + 1
Equation: {{{(i)^2 + (i + 1)^2 = 85}}}
{{{i^2 + i^2 + 2i + 1 = 85}}}
{{{2i^2 + 2i - 84 = 0}}}
{{{i^2 + i - 42 = 0}}}
{{{(i + 7)(i - 6) = 0}}}
i = -7 and i = 6
Six is the only positive number:
first integer = i = 6
second integer = i + 1 = 7
6 and 7