Question 473602
Solve for x. (base is the x-3) 
1+4/3log(x-3)4=11/3
**
1+4/3log(x-3)4=11/3
4/3log(x-3)4=11/3-1
4/3log(x-3)4=11/3-3/3=8/3
log(x-3)4=24/12=2
convert to exponential form: (base(x-3) raised to log of number(2)=number(4)
(x-3)^2=4
x^2-6x+9=4
x^2-6x+5=0
(x-5)(x-1)=0
x=5
or 
x=1 (reject, (x-3)>1)
Check: For x=5
1+4/3log(x-3)4
1+4/3log(5-3)4
1+4/3log(2)4
1+(4/3)*2=8/3+1=8/3+3/3=11/3