Question 49022
Given point (3, 0) and y-intercept (0, 2)
Since you are given two points, first find the slope: 
m =(y2-y1)/(x2-x1)[Slope formula]
m = (2-0)/(0-3) [Plug-in the values]
m = 2/-3 or -2/3
.
Next, use the slope-intercept format:
y = mx + b
0 = (-2/3)(3) + b [Plug-in the values using one of the points and the slope]
0 = -2 + b [Simplify]
2 = b [Solve for "b"]
y = (-2/3)x + 2 [Plug-in the values of "m" and the y-intercept for the equation of the line]