Question 473389
Robert has a box of nickels, dimes and quarters. There are a total of 28 coins in the box. The total value of the coins is $4.95 and there are five more nickels than dimes. How many of each type of coin does Robert have?
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Equations:
n   +  d  +  q  = 28
5n  +10d  +25q = 495
n   -  d  +  0 =  5
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Solve by any method you know to get:
n = 8
d = 3
q = 17
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Cheers,
Stan H.