Question 473522
Let the length of the side of the square be x.
Then the dimensions of the rectangle are: 1/2x and 3x +4
Perimeter of square = 4x
Perimeter of rectangle = 1/2x + 1/2x + (3x+4) +(3x+4) = 7x + 8
Twice the perimeter of square is 8x.
Then equation is:
8x = 7x + 8
Subtract 7x on both sides
x = 8
--> 1/2(8) = 4, 3(8)+4 = 28
Therefore dimensions of rectangle are 28 by 4.