Question 473513
{{{abs((5-2x)/6) <= 3}}}
Since we are dealing with an absolute value you have to deal with the negative case as well.
{{{(5-2x)/6}}} can be any number from -3 to 3 because the absolute value turn all the negative values positive
Rewrite inequality without absolute value signs
{{{-3 <= (5-2x)/6 <= 3}}}
Now you multiply equation by 6
{{{-18 <= 5-2x <= 18}}}
Subtract 5 from both sides
{{{-23 <= -2x <= 13}}}
Divide by -2 on both sides
**Important: when dividing by a negative flip the inequality**
EX: -x < 3 = x > -3 , If you change the sign then flip the inequality.
After dividing and flipping the inequality
{{{23/2 >= x >= -13/2}}}
Interval notation, use brackets for ">=" parenthesis for ">"
x is any real number in [-6.5, 11.5]