Question 473335

{{{(w+1/5)(w+1/4)}}}

{{{w^2+(1/5)w+(1/4)w+(1/5)(1/4)}}}


={{{w^2+(1*4/5*4)w+(1*5/4*5)w+(1/20)}}}


={{{w^2+(4/20)w+(5/20)w+(1/20)}}}


={{{w^2+(9/20)w+(1/20)}}}

={{{20w^2+9w+1}}}


Find the {{{x- intercept}}} for the graph of the equation.
I guess you have:

{{{y=x^2-3x-10}}}.....set {{{y=0}}} and solve for {{{x}}}

{{{0+x^2-3x-10}}}

{{{x^2-3x-10=0}}}.....use quadratic formula

*[invoke quadratic_formula 1, -3, -10, "x"]


{{{ graph( 500, 500, -15,10, -15, 10, x^2-3x-10) }}}