Question 473392
The total number of reds and blues was one greater than the number of greens.
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The sum of three times the number of reds and twice the number of blues exceeded the number of greens by nine.
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How many of each color were there if three times the number of blues exceeded the number of greens by two?
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Equations:
r + b = g + 1
3r + 2b = g +9
3b = g + 2
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Rearrange:
r  + b  - g  = 1
3r +2b  - g  = 9
0r + 3b - g  = 2
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Solve by any method you know to get:
r = 3
b = 2
g = 4
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Cheers,
Stan H.