<PRE><B>Question 473350</B>
During the first part of a trip, a canoeist travels 94 miles at a certain speed.
dist = 94 miles ; rate = x mph ; time = 94/x hrs
------------------------------------

The canoeist travels 15 miles on the second part of the trip at a speed 5 mph slower.
dist = 15 miles ; rate = x-5 ; time = 15/(x-4) hrs
---------------------------------------

The total time for the trip is 4 hours. 
time + time = 4 hrs
94/x + 15/(x-5) = 4
---
94(x-4) + 15x = 4x(x-5)
94x-376 + 15x = 4x^2-20x
109x - 376 = 4x^2-20x
---
4x^2-129x+376 = 0
x = 29 mph (1st leg speed)
x-5 = 24 mph (2nd leg speed
=========
Cheers,
Stan H.


What was the speed on the FIRST part of the trip? What was the speed on the SECOND part of the trip? 
</PRE>