Question 473310
Solve the linear system: 
x-3y=-16,2x-7y=33

Solution 

x-3y=-16	…………….1
2x-7y=33 	….………..2

Multiply equation 1 by -2 (to eliminate x)
-2x+6y=32  ……………3
Now add equation 3 and equation 2
-2x+6y=32  
2x-7y=33
--------------------
-y=65 or y=-65
Put value of y in either equation 1 or 2 to get the value of x
x-3y=-16
x-3(-65)=-16
x+195=-16
x=-16-195
x=-211

(x,y)=(-211, -65)

Check your answer:-
Put values of x and y in either 1 or 2 equations

x-3y=-16				
-211-3(-65)=-16				
-211+195=-16				
-16=-16					


2x-7y=33
2(-211)-7(-65)=33
-422+455=33
33=33