Question 473285
Let J = # of beads Jack has, M = # of beads Mark has, and B = # of beads Ben has



Since "Jack and Mark have 49 beads", we know that {{{J+M=49}}}. Solve for M to get {{{M=49-J}}}



Because "Mark and Ben have 37 beads", we know that {{{M+B=37}}}. Plug in {{{M=49-J}}} to get {{{(49-J)+B=37}}}. Now solve for B to get {{{B=37-49+J}}} ---> {{{B=-12+J}}}



Since "Jack and Ben have 60 beads", we see that {{{J+B=60}}}. Plug in {{{B=-12+J}}} to get {{{J+(-12+J)=60}}}, which will simplify to {{{2J-12=60}}}



Now solve for J



{{{2J-12=60}}}



{{{2J=60+12}}}



{{{2J=72}}}



{{{J=72/2}}}



{{{J=36}}}



So Jack has 36 beads.



So Mark has {{{M=49-J=49-36=13}}} beads



So Ben has {{{B=-12+J=-12+36=24}}} beads



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Answer:


Jack has 36 beads, Mark has 13 beads, and Ben has 24 beads.



In total, they have 36+13+24 = 73 beads