<PRE><B>Question 473277</B>
Find 3 consecutive odd integers such that 4 less than twice the second has the same value as 3 times the number that is one more than the third 
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2(2x+1)-4 = 3(2x+4)
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4x-2 = 6x+12
2x = -14
x = -7
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1st: 2x-1 = -15
2nd: 2x+1 = -13
3rd: 2x+3 = -11
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Cheers,
Stan H.
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