Question 473266


First let's find the slope of the line through the points *[Tex \LARGE \left(-3,-4\right)] and *[Tex \LARGE \left(-8,-1\right)]



Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-3,-4\right)]. So this means that {{{x[1]=-3}}} and {{{y[1]=-4}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-8,-1\right)].  So this means that {{{x[2]=-8}}} and {{{y[2]=-1}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-1--4)/(-8--3)}}} Plug in {{{y[2]=-1}}}, {{{y[1]=-4}}}, {{{x[2]=-8}}}, and {{{x[1]=-3}}}



{{{m=(3)/(-8--3)}}} Subtract {{{-4}}} from {{{-1}}} to get {{{3}}}



{{{m=(3)/(-5)}}} Subtract {{{-3}}} from {{{-8}}} to get {{{-5}}}



{{{m=-3/5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-3,-4\right)] and *[Tex \LARGE \left(-8,-1\right)] is {{{m=-3/5}}}



Now let's use the point slope formula:



{{{y-y[1]=m(x-x[1])}}} Start with the point slope formula



{{{y--4=(-3/5)(x--3)}}} Plug in {{{m=-3/5}}}, {{{x[1]=-3}}}, and {{{y[1]=-4}}}



{{{y--4=(-3/5)(x+3)}}} Rewrite {{{x--3}}} as {{{x+3}}}



{{{y+4=(-3/5)(x+3)}}} Rewrite {{{y--4}}} as {{{y+4}}}



{{{y+4=(-3/5)x+(-3/5)(3)}}} Distribute



{{{y+4=(-3/5)x-9/5}}} Multiply



{{{y=(-3/5)x-9/5-4}}} Subtract 4 from both sides. 



{{{y=(-3/5)x-29/5}}} Combine like terms. note: If you need help with fractions, check out this <a href="http://www.algebra.com/algebra/homework/NumericFractions/fractions-solver.solver">solver</a>.



So the equation that goes through the points *[Tex \LARGE \left(-3,-4\right)] and *[Tex \LARGE \left(-8,-1\right)] is {{{y=(-3/5)x-29/5}}}