Question 473185
3 log<sub>3</sub>(4x + 3) + 6 log<sub>3</sub>(2x - 5) =
log<sub>3</sub>(4x + 3)<sup>3</sup> + log<sub>3</sub>(2x - 5)<sup>6</sup> =
log<sub>3</sub>(4x + 3)<sup>3</sup>(2x - 5)<sup>6</sup>
<br>or<br>
3 log<sub>3</sub>(4x + 3) + 6 log<sub>3</sub>(2x - 5) =
3 log<sub>3</sub>(4x + 3) + 3 log<sub>3</sub>(2x - 5)<sup>2</sup> =
3 log<sub>3</sub>(4x + 3)(2x - 5)<sup>2</sup>