<PRE><B>Question 473139</B>
(x+4)/(x^2+6x+9) - 1/(x^2-9) i dont get it because it says the sum but has a minus sign here are the options:
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(x+4)/(x+3)^2 - 1/[(x-3)(x+3)]
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least common denominator: (x-3)(x+3)^2
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Rewrite each fraction with the lcd as its denominator:
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[(x+4)(x-3)]/lcd - (x+3)/lcd
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Combine the numerators over the lcd:
[x^2+x-12-x-3]/lcd
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= [x^2-15]/[(x-3)(x+3)^2]
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Cheers,
Stan H.
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A) x2-x-15 
(x+3)^2(x-3 
B) x2+x-15 
(x+3)^2(x-3) 
C) x2-15 
(x+3)^2(x-3) 
D) x2-15 
(x-3)^2(x+3) 

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