Question 48981
{{{x = sqrt(2x + 48)}}}
{{{x^2 = 2x + 48}}}
{{{x^2 - 2x - 48 = 0}}}
{{{(x - 8)(x + 6) = 0}}}
x = 8 and x = -6
A square root of a number can not equal a negative number, so the only answer is eight.