Question 472846
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
5^(4x)=125^(x+2)
5^(4x)=((5)^3)^(x+2)
5^(4x)= (5)^3(x+2)
  4x = 3(x+2)
   x = 6

{{{a^0 = 1}}}
{{{(a^p)^q = a^(p*q)}}} ****
{{{root(a,p)*root(a,q) = root(a,p*q)}}}
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}