Question 48953
how do i graph the equation y=3x+2 using only the slope and y-intercept and not my calculator?
Y INTERCEPT IS 2..SO PLOT A POINT AT 2 UNITS FROM ORIGIN ON Y AXIS SAY P.IT IS (0,2)
SLOPE IS 3...THAT IS (Y2-Y1)/(X2-X1)=3...SO CORRESPONDING TO INTERCEPT OF 2 UNITS ON Y AXIS,TAKE -2/3 UNITS ON X AXIS FROM ORIGIN MARKING IT AS Q (-2/3,0).
JOIN PQ AND EXTEND TO GET THE LINE
  {{{ graph( 600, 600, -10, 10, -10, 10, 3*x+2) }}}