<PRE><B>Question 472661</B>
I am trying to solve the following problem. Find the missing dimension of a rectangle. 
A=2x^2+x-6 
w=x+2 
A=lw 
2x^2+x-6=l(x+2) Solve for l 
(2x^2+x-6)/(x+2)=l 
This is as far as I have gotten. Will you please show me step by step how to get to this answer: 
l=2x-3
**
The other missing dimension is the width which is given as w=x+2

A=lw=(2x-3)(x+2)=2x^2+x-6</PRE>