Question 472190
simplify each complex fraction.
{{{2/((c+1))}}} - 1
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 2 + {{{5/((c+1))}}}
:
Put each over a single denominator
{{{(2-1(c+1))/((c+1))}}}
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{{{(2(c+1)+5)/((c+1))}}}
:
Combine like terms
{{{(2-c-1))/((c+1))}}}
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{{{(2c+2+5)/((c+1))}}}
:
{{{(-c+1)/((c+1))}}}
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{{{(2c+7)/((c+1))}}}
:
Invert the dividing fraction and multiply, cancel (c+1)
{{{(-c+1)/((c+1))}}} * {{{(c+1)/(2c+7)}}} = {{{(-c+1)/(2c+7)}}}