Question 472459
y=-2x^2+7x-6
set y to 0 and solve for x:
0=-2x^2+7x-6
0= 2x^2-7x+6
0= (2x-3)(x-2)
x = {3/2, 2}
.
so the two x-intercepts are at:
(3/2, 0) and (2, 0)