Question 472369
{{{8^3*b^4/(24*a^2*b^6)}}}......use the quotient rule {{{b^4/b^6=b(4-6)=b^(-2)=1/b^2}}}


{{{(512*cross(b^4))/(24*a^2*b^cross(6))^2}}}.....divide both {{{512}}} and {{{24}}} by {{{8}}}

{{{(cross(512)64*cross(b^4))/(cross(24)3*a^2*b^cross(6))^2}}}


{{{64/(3a^2*b^2)}}}