Question 472320
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Hi,
*[tex \LARGE\ \ log_bx - log_by = log_b(x/y) ]

*[tex \LARGE\ \ log_7(3t+1)(t-2) - log_7(t-2) = log_7(3t + 1)= 1 ]
  3t + 1 = 7^1
      t = 2   Extraneous solution.  log[7] (t-2) cannot be log[7](0)
Therefore there is NO solution.
*[tex \large \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]