Question 472123
I Think it should be {{{3x^2}}}

3x^2+25x+50

Find the roots of the equation by quadratic formula							
							
a=	3	b=	25	c=	50		
							
b^2-4ac=	625	-	-600				
b^2-4ac=	25	
{{{sqrt(	25	)}}}=	5
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	-25	+	5	)/	6		
x1=	-3.33		-3 1/3				
x2=(	-25	-5	) /	6			
x2= 	-5		-5    						
x	=	-3.33	mph
(x+5)(x+3.33)	
m.ananth@hotmail.ca