Question 472022
Given the distance between (x,1) and (-2,5) is 2{{{ sqrt( 7) }}}, find the value(s) of x.
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{{{d^2 = diffy^2 + diffx^2}}}
{{{28 = 4^2 + (x + 2)^2}}}
{{{(x+2)^2 = 12}}}
x = sqrt(12) - 2 = 2sqrt(3) - 2
x = -sqrt(12) - 2 = -2sqrt(3) - 2