Question 472006
x-5[x-4x(x-3)]=24
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Work form inside the brackets to outside the brackets:
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x-5[x-4x^2+12x] = 24
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x-5[-4x^2+13x] = 24
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x +20x^2-65x = 24
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20x^2-64x-24 = 0
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5x^2-16x-6 = 0
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x = [16 +- sqrt(16^2-4*5*-6)]/10
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x = [16 +- sqrt(376)]/10
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x = [16 +- 19.4]/10
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Cheers,
Stan H.
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