Question 471807
f(x) = x^3 + 8x^2 + 22x + 20  
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I graphed "f" and found a Real root at x = -2
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Then, using synthetic division I get:
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-2)....1...8....22....20
........1...6....10...|..0
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Solve x^2+6x+10 = 0
x = [-6 +- sqrt(36-4*10)]/2
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x = [-6 +- sqrt(-4)]/2
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x = -3 +- i
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Answer: A
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cheers,
Stan H.
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A. {{{  f(x)=(x+2)(x+3+i)(x+3-i)  }}}
B. {{{  f(x)=(x+2)(x+3+i)(x-3-i)  }}}
C. {{{  f(x)=(x-1)(x+3+i(sqrt3))(x+3-i(sqrt3))  }}}
D. {{{  f(x)=(x+1)(x+3+i(sqrt3))(x-2-i(sqrt3))  }}}