Question 48853
Q: The sum of the squares of two consecutive odd integers decreased by the product of the integers is the same as 67. 

Comment:
Even numbers must be symbolized as multiples of two, e.g. 2x, 2(x+1), etc.
Odd numbers are always 1 more than some even number. They must be symbolized
as 2x+1 or 2x+3 etc.
--------------------
So for your problem
Two consecutive odd integers are 
1st: 2x+1
2nd: 2x+3
EQUATION:
(2x+1)^2+(2x+3)^2-(2x+1)(2x+3)=67
Solve this equation for x.
Then find 2x+1 and 2x+3
Cheers,
Stan H.