Question 471260
We know that x+y is odd, so this implies that exactly one of x,y is odd. y/x is also an odd integer, so we can say that y = kx, where k is odd. If x is even, then y is also even (e.g. we can have x = 2 and y = 18), and if x is odd, y is odd. However, this contradicts our first statement since the second statement implies that none or both of the integers are odd. Hence, the situation is impossible.