Question 471419
{{{ log(2,(3x-2))=1+log(2,5) }}}
Use {{{log(a,a)=1}}}, let look at {{{1=log(2,2)}}}
{{{ log(2,(3x-2))=log(2,2)+log(2,5) }}}
Use formula {{{log(c,a)+log(c,b)=log(c,ab)}}}
{{{ log(2,(3x-2))=log(2,2*5) }}}
{{{ log(2,(3x-2))=log(2,10) }}}
{{{3x-2=10}}}
{{{3x=10+2}}}
{{{3x=12}}}
{{{x=12/3}}}
{{{x=4}}}