Question 471171
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Hi,
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p(phobic) = .16 & q = .84 and  n = 2
nCx = {{{n!/(x!(n-x)!)}}}
 P(both phobic) = (.16)^2 = .0256
 P(at least one phobic) = 1 -P(none) = 1 -(.84)^2 = 1 - .7056 = .2944