Question 471160
{{{Db=10log(5.3*10^-5/10^-16)=10log(5.3*10^(-5-(-16)))=10log(5.3*10^11)=10(log(5.3)+log(10^11))=10(log(5.3)+11log(10))=10(log(5.3)+11)}}}
If you need more, have to use scientific calculator
{{{10(log(5.3)+11)=10(0.7243+11)=117.243}}}