Question 471131
(log2x+logx)/(log2x-logx)=3
{{{log(2x^2)/log(2) = 3}}}
{{{log(2x^2) = 3log(2) = log(2^3) = log(8)}}}
{{{2x^2 = 8}}}
x = 2
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x = -2 is rejected due to the logs