Question 470631
When r is increased by 25% it becomes {{{(125/100)*r}}} and the volume of the can 

changed to {{{(125/100)^2}}}.

When h is decreased by x% it becomes {{{(100-x)/100*h}}}. Since the volume of the 

can does not change we write the equation:

{{{(100/125)^2=(100-x)/100}}} solving this equation we get:

{{{(10000/125^2)*100=100-x}}}<=>{{{x=100-(1000000/125^2)}}}<=>{{{x=36}}}

Answer:The height is decreased by 36%.